- gf25031 的博客
排序
- @ 2026-5-26 13:48:21

冒泡排序
void bubbleSort(int a[], int n) {
for (int i = 0; i < n-1; i++) {
bool flag = false; // 优化:无交换则提前退出
for (int j = 0; j < n-i-1; j++) {
if (a[j] > a[j+1]) {
swap(a[j], a[j+1]);
flag = true;
}
}
if (!flag) break;
}
}
选择排序
void selectionSort(int a[], int n) {
for (int i = 0; i < n; i++) {
int minPos = i;
for (int j = i+1; j < n; j++) {
if (a[j] < a[minPos]) minPos = j;
}
swap(a[i], a[minPos]);
}
}
排序
void insertionSort(int a[], int n) {
for (int i = 1; i < n; i++) {
int key = a[i];
int j = i - 1;
while (j >= 0 && a[j] > key) {
a[j+1] = a[j];
j--;
}
a[j+1] = key;
}
}
希尔排序
void shellSort(int a[], int n) {
for (int gap = n / 2; gap > 0; gap /= 2) {
for (int i = gap; i < n; i++) {
int key = a[i];
int j;
for (j = i; j >= gap && a[j - gap] > key; j -= gap) {
a[j] = a[j - gap];
}
a[j] = key;
}
}
}
归并排序
void merge(int a[], int l, int mid, int r) {
int temp[MAXN];
int i = l, j = mid + 1, k = 0;
while (i <= mid && j <= r) {
if (a[i] <= a[j]) temp[k++] = a[i++];
else temp[k++] = a[j++];
}
while (i <= mid) temp[k++] = a[i++];
while (j <= r) temp[k++] = a[j++];
for (i = 0; i < k; i++) a[l + i] = temp[i];
}
void mergeSort(int a[], int l, int r) {
if (l >= r) return;
int mid = (l + r) / 2;
mergeSort(a, l, mid);
mergeSort(a, mid + 1, r);
merge(a, l, mid, r);
}
快速排序
void quickSort(int a[], int l, int r) {
if (l >= r) return;
int i = l, j = r, pivot = a[l];
while (i < j) {
while (i < j && a[j] >= pivot) j--;
a[i] = a[j];
while (i < j && a[i] <= pivot) i++;
a[j] = a[i];
}
a[i] = pivot;
quickSort(a, l, i-1);
quickSort(a, i+1, r);
}
堆排序
void heapify(int a[], int n, int i) {
int largest = i;
int left = 2*i+1;
int right = 2*i+2;
if (left < n && a[left] > a[largest]) largest = left;
if (right < n && a[right] > a[largest]) largest = right;
if (largest != i) {
swap(a[i], a[largest]);
heapify(a, n, largest);
}
}
void heapSort(int a[], int n) {
for (int i = n/2-1; i >= 0; i--) heapify(a, n, i);
for (int i = n-1; i > 0; i--) {
swap(a[0], a[i]);
heapify(a, i, 0);
}
}
计数排序
void countingSort(int a[], int n, int maxVal) {
int* cnt = new int[maxVal + 1](); // 动态分配
for (int i = 0; i < n; i++) cnt[a[i]]++;
int k = 0;
for (int i = 0; i <= maxVal; i++) {
while (cnt[i] > 0) {
a[k++] = i;
cnt[i]--;
}
}
delete[] cnt;
}
桶排
void bucketSort(int a[], int n, int maxVal) {
int bucketSize = 10; // 桶的数量,可调整
vector<int>* buckets = new vector<int>[bucketSize];
// 分配元素到桶
for (int i = 0; i < n; i++) {
int idx = (a[i] * bucketSize) / (maxVal + 1);
buckets[idx].push_back(a[i]);
}
// 桶内排序(用插入排序)
for (int i = 0; i < bucketSize; i++) {
insertionSort(buckets[i].data(), buckets[i].size());
}
// 合并桶
int k = 0;
for (int i = 0; i < bucketSize; i++) {
for (int num : buckets[i]) a[k++] = num;
}
delete[] buckets;
}
基数排序
void radixSort(int a[], int n) {
int maxVal = *max_element(a, a + n);
// 按每一位排序
for (int exp = 1; maxVal / exp > 0; exp *= 10) {
vector<int> output(n);
int cnt[10] = {0};
// 统计每个数字的出现次数
for (int i = 0; i < n; i++) cnt[(a[i]/exp)%10]++;
// 计算位置
for (int i = 1; i < 10; i++) cnt[i] += cnt[i-1];
// 反向填充,保证稳定性
for (int i = n-1; i >= 0; i--) {
int digit = (a[i]/exp) % 10;
output[cnt[digit] - 1] = a[i];
cnt[digit]--;
}
// 复制回原数组
for (int i = 0; i < n; i++) a[i] = output[i];
}
}